Summary


Interactions between Output and Capital

The Solow model, which we will discuss in the next few lectures, adds in saving to our previous models.

Assume 𝑁 is constant (no population growth) and recall from modeling growth that

π‘Œπ‘‘π‘=𝑓(𝐾𝑑𝑁)𝑓′>0,𝑓″<0

where 𝑓′>0 means more capital per worker increases output, and 𝑓″<0 captures decreasing returns to capital.

Assume the economy is closed with no public deficit, so investment equals saving: 𝐼𝑑=𝑆𝑑. (This is how we derived IS - investment = savings). Moreover, assume private saving is proportional to income, 𝑆=π‘ π‘Œ where π‘ βˆˆ(0,1) is the saving rate, so

𝐼𝑑=π‘ π‘Œπ‘‘

Capital Accumulation

Capital stock evolves as

𝐾𝑑+1=(1βˆ’π›Ώ)𝐾𝑑+𝐼𝑑

where 𝛿 is the depreciation rate. In per-worker terms:

𝐾𝑑+1𝑁=(1βˆ’π›Ώ)𝐾𝑑𝑁+π‘ π‘Œπ‘‘π‘

The change in capital per worker is saving per worker minus depreciation per worker. Substituting π‘Œπ‘‘π‘=𝑓(𝐾𝑑𝑁):

𝐾𝑑+1π‘βˆ’πΎπ‘‘π‘=𝑠𝑓(𝐾𝑑𝑁)βˆ’π›ΏπΎπ‘‘π‘

This is the key equation: capital per worker grows when investment per worker (𝑠𝑓(𝐾𝑑𝑁)) exceeds depreciation per worker (𝛿𝐾𝑑𝑁).

Example

An increase in the saving rate shifts the investment curve up, raising the steady-state level of capital and output per worker.

Steady State

In the steady state, capital per worker is constant (𝐾𝑑+1𝑁=𝐾𝑑𝑁), so investment exactly offsets depreciation: s f(K^*/N) = delta K^*/N.

We can also find the saving rate that maximizes steady-state consumption per worker:

To get a sense of magnitudes, assume π‘Œ=βˆšπΎβˆšπ‘ so that

𝐾𝑑+1π‘βˆ’πΎπ‘‘π‘=π‘ βˆšπΎπ‘‘π‘βˆ’π›ΏπΎπ‘‘π‘

Setting the left side to zero and solving:

K^*/N = (s/delta)^2 \ Y^*/N = sqrt(K^*/N) = s/delta

So in the long run, doubling the saving rate doubles output per worker. However, it takes a long time to reach the new steady state, even when we double the saving rate: Similarly, the effect on output growth rate decays slowly back to zero:

Adding Population Growth

If there is population growth at rate 𝑔𝑁, capital per worker is now β€œdiluted” by the growing workforce. The equation becomes:

𝐾𝑑+1𝑁𝑑+1=𝑠𝑓(𝐾𝑑𝑁𝑑)βˆ’(𝛿+𝑔𝑁)𝐾𝑑𝑁𝑑

Population growth acts like additional depreciation: you need more investment just to keep capital per worker constant.

Example

Assume 𝑔𝐴=0 (no technological progress).